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200211111331221 = 366737037110407
BaseRepresentation
bin101101100001011101001000…
…001010111100010110010101
3222020212222212120211212000210
4231201131020022330112111
5202220224324000044341
61545451414222000033
760112526660112264
oct5541351012742625
9866788776755023
10200211111331221
1158880067943111
121a556308116019
138793a995b5953
1437623ab6b65db
151822e3cc44c16
hexb617482bc595

200211111331221 has 4 divisors (see below), whose sum is σ = 266948148441632. Its totient is φ = 133474074220812.

The previous prime is 200211111331207. The next prime is 200211111331223. The reversal of 200211111331221 is 122133111112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 200211111331221 - 213 = 200211111323029 is a prime.

It is a super-5 number, since 5×2002111113312215 (a number of 73 digits) contains 55555 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200211111331223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33368518555201 + ... + 33368518555206.

It is an arithmetic number, because the mean of its divisors is an integer number (66737037110408).

Almost surely, 2200211111331221 is an apocalyptic number.

It is an amenable number.

200211111331221 is a deficient number, since it is larger than the sum of its proper divisors (66737037110411).

200211111331221 is an equidigital number, since it uses as much as digits as its factorization.

200211111331221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66737037110410.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 200211111331221 its reverse (122133111112002), we get a palindrome (322344222443223).

The spelling of 200211111331221 in words is "two hundred trillion, two hundred eleven billion, one hundred eleven million, three hundred thirty-one thousand, two hundred twenty-one".

Divisors: 1 3 66737037110407 200211111331221