2002112000113 has 4 divisors (see below), whose sum is σ = 2089160347968. Its totient is φ = 1915063652260.

The previous prime is 2002112000111. The next prime is 2002112000117. The reversal of 2002112000113 is 3110002112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002112000113 - 2¹ = 2002112000111 is a prime.

It is a super-3 number, since 3×2002112000113³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2002112000093 and 2002112000102.

It is not an unprimeable number, because it can be changed into a prime (2002112000111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43524173893 + ... + 43524173938.

It is an arithmetic number, because the mean of its divisors is an integer number (522290086992).

Almost surely, 2^{2002112000113} is an apocalyptic number.

2002112000113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

2002112000113 is a deficient number, since it is larger than the sum of its proper divisors (87048347855).

2002112000113 is an equidigital number, since it uses as much as digits as its factorization.

2002112000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87048347854.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 2002112000113 its reverse (3110002112002), we get a palindrome (5112114112115).

The spelling of 2002112000113 in words is "two trillion, two billion, one hundred twelve million, one hundred thirteen", and thus it is an aban number.