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20021122535 = 590714932957
BaseRepresentation
bin10010101001010110…
…100001010111100111
31220200022021101220212
4102221112201113213
5312000401410120
613110402050035
71306066506431
oct225126412747
956608241825
1020021122535
118544446767
123a6904991b
131b70b91c8b
14d7d023651
157c2a3e6c5
hex4a95a15e7

20021122535 has 16 divisors (see below), whose sum is σ = 24076084896. Its totient is φ = 15983115648.

The previous prime is 20021122531. The next prime is 20021122571. The reversal of 20021122535 is 53522112002.

It is a cyclic number.

It is not a de Polignac number, because 20021122535 - 22 = 20021122531 is a prime.

It is a super-3 number, since 3×200211225353 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20021122535.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20021122531) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6769277 + ... + 6772233.

It is an arithmetic number, because the mean of its divisors is an integer number (1504755306).

Almost surely, 220021122535 is an apocalyptic number.

20021122535 is a deficient number, since it is larger than the sum of its proper divisors (4054962361).

20021122535 is a wasteful number, since it uses less digits than its factorization.

20021122535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5362.

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 20021122535 its reverse (53522112002), we get a palindrome (73543234537).

The spelling of 20021122535 in words is "twenty billion, twenty-one million, one hundred twenty-two thousand, five hundred thirty-five".

Divisors: 1 5 907 1493 2957 4535 7465 14785 1354151 2681999 4414801 6770755 13409995 22074005 4004224507 20021122535