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200211320013 = 3155699428629
BaseRepresentation
bin1011101001110110000…
…1100100110011001101
3201010210001220212001120
42322131201210303031
511240013044220023
6231550435231153
720315265066225
oct2723541446315
9633701825046
10200211320013
1177a00086041
12329764484b9
1315b5903aac3
1499941ad085
15531bcb78e3
hex2e9d864ccd

200211320013 has 8 divisors (see below), whose sum is σ = 266950764000. Its totient is φ = 133473044688.

The previous prime is 200211320011. The next prime is 200211320017. The reversal of 200211320013 is 310023112002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 200211320013 - 21 = 200211320011 is a prime.

It is a super-2 number, since 2×2002113200132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200211319974 and 200211320001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200211320011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 252783 + ... + 681411.

It is an arithmetic number, because the mean of its divisors is an integer number (33368845500).

Almost surely, 2200211320013 is an apocalyptic number.

It is an amenable number.

200211320013 is a deficient number, since it is larger than the sum of its proper divisors (66739443987).

200211320013 is a wasteful number, since it uses less digits than its factorization.

200211320013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 584331.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 200211320013 its reverse (310023112002), we get a palindrome (510234432015).

The spelling of 200211320013 in words is "two hundred billion, two hundred eleven million, three hundred twenty thousand, thirteen".

Divisors: 1 3 155699 428629 467097 1285887 66737106671 200211320013