Base | Representation |
---|---|
bin | 101101100001011101010100… |
… | …101000000110001010110101 |
3 | 222020220000102011001120121002 |
4 | 231201131110220012022311 |
5 | 202220230240444101323 |
6 | 1545451451044533045 |
7 | 60112535105243315 |
oct | 5541352450061265 |
9 | 866800364046532 |
10 | 200211320300213 |
11 | 588801648a1662 |
12 | 1a5563660b1185 |
13 | 8793b00990441 |
14 | 37623cb351445 |
15 | 1822e51271828 |
hex | b61754a062b5 |
200211320300213 has 4 divisors (see below), whose sum is σ = 200990352675180. Its totient is φ = 199432287925248.
The previous prime is 200211320300209. The next prime is 200211320300237. The reversal of 200211320300213 is 312003023112002.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 191021340176209 + 9189980124004 = 13821047^2 + 3031498^2 .
It is a cyclic number.
It is not a de Polignac number, because 200211320300213 - 22 = 200211320300209 is a prime.
It is a super-2 number, since 2×2002113203002132 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200211320300413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389516187098 + ... + 389516187611.
It is an arithmetic number, because the mean of its divisors is an integer number (50247588168795).
Almost surely, 2200211320300213 is an apocalyptic number.
It is an amenable number.
200211320300213 is a deficient number, since it is larger than the sum of its proper divisors (779032374967).
200211320300213 is an equidigital number, since it uses as much as digits as its factorization.
200211320300213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 779032374966.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 200211320300213 its reverse (312003023112002), we get a palindrome (512214343412215).
The spelling of 200211320300213 in words is "two hundred trillion, two hundred eleven billion, three hundred twenty million, three hundred thousand, two hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •