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2002113301 = 8324121847
BaseRepresentation
bin111011101010101…
…1101001100010101
312011112022220010111
41313111131030111
513100020111201
6530400123021
7100420453006
oct16725351425
95145286114
102002113301
119381603a1
1247a606471
1325ba37236
1414dc891ad
15bab7db51
hex7755d315

2002113301 has 4 divisors (see below), whose sum is σ = 2026235232. Its totient is φ = 1977991372.

The previous prime is 2002113299. The next prime is 2002113343. The reversal of 2002113301 is 1033112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002113301 - 21 = 2002113299 is a prime.

It is a super-2 number, since 2×20021133012 = 8016915340082233202, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002113371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12060841 + ... + 12061006.

It is an arithmetic number, because the mean of its divisors is an integer number (506558808).

Almost surely, 22002113301 is an apocalyptic number.

It is an amenable number.

2002113301 is a deficient number, since it is larger than the sum of its proper divisors (24121931).

2002113301 is an equidigital number, since it uses as much as digits as its factorization.

2002113301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24121930.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 2002113301 is about 44744.9807352735. The cubic root of 2002113301 is about 1260.3646590874.

Adding to 2002113301 its reverse (1033112002), we get a palindrome (3035225303).

The spelling of 2002113301 in words is "two billion, two million, one hundred thirteen thousand, three hundred one".

Divisors: 1 83 24121847 2002113301