Base | Representation |
---|---|
bin | 1011101001110110010… |
… | …0100100001110111001 |
3 | 201010210010101200122121 |
4 | 2322131210210032321 |
5 | 11240013244312441 |
6 | 231550504121241 |
7 | 20315304543241 |
oct | 2723544441671 |
9 | 633703350577 |
10 | 200212104121 |
11 | 77a00571167 |
12 | 32976766221 |
13 | 15b59253983 |
14 | 9994334b21 |
15 | 531bdbedd1 |
hex | 2e9d9243b9 |
200212104121 has 4 divisors (see below), whose sum is σ = 200375811072. Its totient is φ = 200048397172.
The previous prime is 200212104077. The next prime is 200212104143. The reversal of 200212104121 is 121401212002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 200212104121 - 219 = 200211579833 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200212104095 and 200212104104.
It is not an unprimeable number, because it can be changed into a prime (200212104181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81851641 + ... + 81854086.
It is an arithmetic number, because the mean of its divisors is an integer number (50093952768).
Almost surely, 2200212104121 is an apocalyptic number.
It is an amenable number.
200212104121 is a deficient number, since it is larger than the sum of its proper divisors (163706951).
200212104121 is a wasteful number, since it uses less digits than its factorization.
200212104121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163706950.
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 200212104121 its reverse (121401212002), we get a palindrome (321613316123).
The spelling of 200212104121 in words is "two hundred billion, two hundred twelve million, one hundred four thousand, one hundred twenty-one".
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