200212120000111 has 4 divisors (see below), whose sum is σ = 200212151293000. Its totient is φ = 200212088707224.

The previous prime is 200212120000073. The next prime is 200212120000141. The reversal of 200212120000111 is 111000021212002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200212120000111 - 2¹¹ = 200212119998063 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200212120000091 and 200212120000100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200212120000141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2194161 + ... + 20130538.

It is an arithmetic number, because the mean of its divisors is an integer number (50053037823250).

Almost surely, 2^{200212120000111} is an apocalyptic number.

200212120000111 is a deficient number, since it is larger than the sum of its proper divisors (31292889).

200212120000111 is an equidigital number, since it uses as much as digits as its factorization.

200212120000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31292888.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 200212120000111 its reverse (111000021212002), we get a palindrome (311212141212113).

The spelling of 200212120000111 in words is "two hundred trillion, two hundred twelve billion, one hundred twenty million, one hundred eleven", and thus it is an aban number.