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2002122022001 = 5038339738047
BaseRepresentation
bin11101001000100111110…
…001011001110001110001
321002101211022210201220112
4131020213301121301301
5230300321214201001
64131432343151105
7264435310252103
oct35104761316161
97071738721815
102002122022001
11702105760382
12284036745495
13116a51092aaa
146cc9062d573
153712e444cbb
hex1d227c59c71

2002122022001 has 4 divisors (see below), whose sum is σ = 2002161810432. Its totient is φ = 2002082233572.

The previous prime is 2002122021989. The next prime is 2002122022003. The reversal of 2002122022001 is 1002202212002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002122022001 - 218 = 2002121759857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002122022003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19818641 + ... + 19919406.

It is an arithmetic number, because the mean of its divisors is an integer number (500540452608).

Almost surely, 22002122022001 is an apocalyptic number.

It is an amenable number.

2002122022001 is a deficient number, since it is larger than the sum of its proper divisors (39788431).

2002122022001 is an equidigital number, since it uses as much as digits as its factorization.

2002122022001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39788430.

The product of its (nonzero) digits is 64, while the sum is 14.

Adding to 2002122022001 its reverse (1002202212002), we get a palindrome (3004324234003).

The spelling of 2002122022001 in words is "two trillion, two billion, one hundred twenty-two million, twenty-two thousand, one".

Divisors: 1 50383 39738047 2002122022001