Search a number
-
+
2002122202103 = 3617553531159
BaseRepresentation
bin11101001000100111110…
…010000101101111110111
321002101211100010212221222
4131020213302011233313
5230300321240431403
64131432351100555
7264435311632142
oct35104762055767
97071740125858
102002122202103
11702105873721
1228403681175b
13116a51126a6a
146cc90679059
153712e47d338
hex1d227c85bf7

2002122202103 has 4 divisors (see below), whose sum is σ = 2002675736880. Its totient is φ = 2001568667328.

The previous prime is 2002122202057. The next prime is 2002122202127. The reversal of 2002122202103 is 3012022212002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002122202103 - 28 = 2002122201847 is a prime.

It is a super-3 number, since 3×20021222021033 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002122202603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 276761963 + ... + 276769196.

It is an arithmetic number, because the mean of its divisors is an integer number (500668934220).

Almost surely, 22002122202103 is an apocalyptic number.

2002122202103 is a deficient number, since it is larger than the sum of its proper divisors (553534777).

2002122202103 is an equidigital number, since it uses as much as digits as its factorization.

2002122202103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 553534776.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 2002122202103 its reverse (3012022212002), we get a palindrome (5014144414105).

The spelling of 2002122202103 in words is "two trillion, two billion, one hundred twenty-two million, two hundred two thousand, one hundred three".

Divisors: 1 3617 553531159 2002122202103