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2002123324555 = 51093673620779
BaseRepresentation
bin11101001000100111110…
…110010111110010001011
321002101211102020220200021
4131020213312113302023
5230300322032341210
64131432431121311
7264435324315454
oct35104766276213
97071742226607
102002123324555
1170210646aa72
12284037073237
13116a5142a933
146cc9088c12b
153712e600bda
hex1d227d97c8b

2002123324555 has 8 divisors (see below), whose sum is σ = 2424589714800. Its totient is φ = 1587004176096.

The previous prime is 2002123324547. The next prime is 2002123324601. The reversal of 2002123324555 is 5554233212002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2002123324555 - 23 = 2002123324547 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2002123324555.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1836809845 + ... + 1836810934.

It is an arithmetic number, because the mean of its divisors is an integer number (303073714350).

Almost surely, 22002123324555 is an apocalyptic number.

2002123324555 is a deficient number, since it is larger than the sum of its proper divisors (422466390245).

2002123324555 is a wasteful number, since it uses less digits than its factorization.

2002123324555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3673620893.

The product of its (nonzero) digits is 72000, while the sum is 34.

Adding to 2002123324555 its reverse (5554233212002), we get a palindrome (7556356536557).

The spelling of 2002123324555 in words is "two trillion, two billion, one hundred twenty-three million, three hundred twenty-four thousand, five hundred fifty-five".

Divisors: 1 5 109 545 3673620779 18368103895 400424664911 2002123324555