Base | Representation |
---|---|
bin | 101101100001011111010001… |
… | …111001110101011110100001 |
3 | 222020220012211121222012012202 |
4 | 231201133101321311132201 |
5 | 202220244042024234213 |
6 | 1545452435405502545 |
7 | 60112641146254505 |
oct | 5541372171653641 |
9 | 866805747865182 |
10 | 200213422102433 |
11 | 58881043250793 |
12 | 1a556851b71a55 |
13 | 879407725c6ac |
14 | 376254a54a305 |
15 | 1823025a42b58 |
hex | b617d1e757a1 |
200213422102433 has 32 divisors (see below), whose sum is σ = 211939653369600. Its totient is φ = 188608384935936.
The previous prime is 200213422102427. The next prime is 200213422102493. The reversal of 200213422102433 is 334201224312002.
It is a cyclic number.
It is not a de Polignac number, because 200213422102433 - 24 = 200213422102417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200213422102396 and 200213422102405.
It is not an unprimeable number, because it can be changed into a prime (200213422102403) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16674718916 + ... + 16674730922.
It is an arithmetic number, because the mean of its divisors is an integer number (6623114167800).
Almost surely, 2200213422102433 is an apocalyptic number.
It is an amenable number.
200213422102433 is a deficient number, since it is larger than the sum of its proper divisors (11726231267167).
200213422102433 is a wasteful number, since it uses less digits than its factorization.
200213422102433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17001.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 200213422102433 its reverse (334201224312002), we get a palindrome (534414646414435).
The spelling of 200213422102433 in words is "two hundred trillion, two hundred thirteen billion, four hundred twenty-two million, one hundred two thousand, four hundred thirty-three".
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