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2002200211311 = 33347199402471
BaseRepresentation
bin11101001000101100011…
…011101010111101101111
321002102000202221011110220
4131020230123222331233
5230301001223230221
64131444215102423
7264440246664216
oct35105433527557
97072022834426
102002200211311
11702145905143
12284058971a13
13116a6433ac61
146cc9ab8407d
153713623c0c6
hex1d22c6eaf6f

2002200211311 has 8 divisors (see below), whose sum is σ = 2670397905024. Its totient is φ = 1334401329240.

The previous prime is 2002200211307. The next prime is 2002200211337. The reversal of 2002200211311 is 1131120022002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2002200211311 - 22 = 2002200211307 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002200211381) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 99691195 + ... + 99711276.

It is an arithmetic number, because the mean of its divisors is an integer number (333799738128).

Almost surely, 22002200211311 is an apocalyptic number.

2002200211311 is a deficient number, since it is larger than the sum of its proper divisors (668197693713).

2002200211311 is a wasteful number, since it uses less digits than its factorization.

2002200211311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 199405821.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 2002200211311 its reverse (1131120022002), we get a palindrome (3133320233313).

It can be divided in two parts, 20022002 and 11311, that multiplied together give a palindrome (226468864622).

The spelling of 2002200211311 in words is "two trillion, two billion, two hundred million, two hundred eleven thousand, three hundred eleven".

Divisors: 1 3 3347 10041 199402471 598207413 667400070437 2002200211311