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20022111122003 = 150732113283243
BaseRepresentation
bin1001000110101110000101…
…10100100011001001010011
32121220002120100102212212022
410203113002310203021103
510111020240421401003
6110330010400122055
74134356402324264
oct443270264431123
977802510385768
1020022111122003
11641a369831291
1222b450460632b
13b23100171993
144d310aa8696b
1524ac4b114738
hex1235c2d23253

20022111122003 has 4 divisors (see below), whose sum is σ = 20022125912568. Its totient is φ = 20022096331440.

The previous prime is 20022111121813. The next prime is 20022111122093. The reversal of 20022111122003 is 30022111122002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20022111122003 - 212 = 20022111117907 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20022111122093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5134301 + ... + 8148942.

It is an arithmetic number, because the mean of its divisors is an integer number (5005531478142).

Almost surely, 220022111122003 is an apocalyptic number.

20022111122003 is a deficient number, since it is larger than the sum of its proper divisors (14790565).

20022111122003 is a wasteful number, since it uses less digits than its factorization.

20022111122003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14790564.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 20022111122003 its reverse (30022111122002), we get a palindrome (50044222244005).

Subtracting 20022111122003 from its reverse (30022111122002), we obtain a palindrome (9999999999999).

The spelling of 20022111122003 in words is "twenty trillion, twenty-two billion, one hundred eleven million, one hundred twenty-two thousand, three".

Divisors: 1 1507321 13283243 20022111122003