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200221212011 = 613282314951
BaseRepresentation
bin1011101001111000011…
…1010011110101101011
3201010210202112102022212
42322132013103311223
511240023112241021
6231551431235335
720315445135662
oct2723607236553
9633722472285
10200221212011
1177a05722047
1232979818b4b
1315b5b0c2462
149995625dd9
15531cabd85b
hex2e9e1d3d6b

200221212011 has 4 divisors (see below), whose sum is σ = 203503527024. Its totient is φ = 196938897000.

The previous prime is 200221212007. The next prime is 200221212049. The reversal of 200221212011 is 110212122002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200221212011 - 22 = 200221212007 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200221212091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1641157415 + ... + 1641157536.

It is an arithmetic number, because the mean of its divisors is an integer number (50875881756).

Almost surely, 2200221212011 is an apocalyptic number.

200221212011 is a deficient number, since it is larger than the sum of its proper divisors (3282315013).

200221212011 is an equidigital number, since it uses as much as digits as its factorization.

200221212011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3282315012.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 200221212011 its reverse (110212122002), we get a palindrome (310433334013).

Subtracting from 200221212011 its reverse (110212122002), we obtain a palindrome (90009090009).

The spelling of 200221212011 in words is "two hundred billion, two hundred twenty-one million, two hundred twelve thousand, eleven".

Divisors: 1 61 3282314951 200221212011