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200221513004832 = 253112332552331883
BaseRepresentation
bin101101100001100110110100…
…001010001011011100100000
3222020220222201111102121202120
4231201212310022023130200
5202220412124312123312
61545500254313544240
760113345512636314
oct5541466412133440
9866828644377676
10200221513004832
1158884515366490
121a55832b715080
138794a6657c3c7
143762ab6d17b44
15182334aee728c
hexb619b428b720

200221513004832 has 192 divisors, whose sum is σ = 575863006957056. Its totient is φ = 60408524072960.

The previous prime is 200221513004831. The next prime is 200221513004879. The reversal of 200221513004832 is 238400315122002.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a junction number, because it is equal to n+sod(n) for n = 200221513004793 and 200221513004802.

It is not an unprimeable number, because it can be changed into a prime (200221513004831) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6279867163 + ... + 6279899045.

It is an arithmetic number, because the mean of its divisors is an integer number (2999286494568).

Almost surely, 2200221513004832 is an apocalyptic number.

200221513004832 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200221513004832, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (287931503478528).

200221513004832 is an abundant number, since it is smaller than the sum of its proper divisors (375641493952224).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200221513004832 is a wasteful number, since it uses less digits than its factorization.

200221513004832 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57663 (or 57655 counting only the distinct ones).

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 200221513004832 its reverse (238400315122002), we get a palindrome (438621828126834).

The spelling of 200221513004832 in words is "two hundred trillion, two hundred twenty-one billion, five hundred thirteen million, four thousand, eight hundred thirty-two".