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20022212121 = 36674070707
BaseRepresentation
bin10010101001011010…
…101011011000011001
31220200101022202112220
4102221122223120121
5312001141241441
613110441254253
71306111665162
oct225132533031
956611282486
1020022212121
11854502034a
123a69494389
131b71183bc2
14d7d228769
157c2ba7466
hex4a96ab619

20022212121 has 4 divisors (see below), whose sum is σ = 26696282832. Its totient is φ = 13348141412.

The previous prime is 20022212113. The next prime is 20022212123. The reversal of 20022212121 is 12121222002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20022212121 - 23 = 20022212113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20022212121.

It is not an unprimeable number, because it can be changed into a prime (20022212123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3337035351 + ... + 3337035356.

It is an arithmetic number, because the mean of its divisors is an integer number (6674070708).

Almost surely, 220022212121 is an apocalyptic number.

It is an amenable number.

20022212121 is a deficient number, since it is larger than the sum of its proper divisors (6674070711).

20022212121 is an equidigital number, since it uses as much as digits as its factorization.

20022212121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6674070710.

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 20022212121 its reverse (12121222002), we get a palindrome (32143434123).

The spelling of 20022212121 in words is "twenty billion, twenty-two million, two hundred twelve thousand, one hundred twenty-one".

Divisors: 1 3 6674070707 20022212121