Base | Representation |
---|---|
bin | 1001000110101110011100… |
… | …11001010001111111100111 |
3 | 2121220010001212211011121211 |
4 | 10203113032121101333213 |
5 | 10111021140124103310 |
6 | 110330041534052251 |
7 | 4134364250654233 |
oct | 443271631217747 |
9 | 77803055734554 |
10 | 20022305300455 |
11 | 641a4593a8447 |
12 | 22b455964a087 |
13 | b2313146b283 |
14 | 4d31287915c3 |
15 | 24ac5d1bdc8a |
hex | 1235ce651fe7 |
20022305300455 has 8 divisors (see below), whose sum is σ = 24148729642752. Its totient is φ = 15936535385568.
The previous prime is 20022305300429. The next prime is 20022305300467. The reversal of 20022305300455 is 55400350322002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20022305300455 - 211 = 20022305298407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10163605767 + ... + 10163607736.
It is an arithmetic number, because the mean of its divisors is an integer number (3018591205344).
Almost surely, 220022305300455 is an apocalyptic number.
20022305300455 is a deficient number, since it is larger than the sum of its proper divisors (4126424342297).
20022305300455 is a wasteful number, since it uses less digits than its factorization.
20022305300455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20327213705.
The product of its (nonzero) digits is 36000, while the sum is 31.
Adding to 20022305300455 its reverse (55400350322002), we get a palindrome (75422655622457).
The spelling of 20022305300455 in words is "twenty trillion, twenty-two billion, three hundred five million, three hundred thousand, four hundred fifty-five".
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