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2002312123103 = 6703298718801
BaseRepresentation
bin11101001000110011000…
…110100101001011011111
321002102022120111212121002
4131020303012211023133
5230301213400414403
64131503253500515
7264443106140525
oct35106306451337
97072276455532
102002312123103
117021a2aa2126
1228408a34173b
13116a81592556
146ccab996315
1537140e96188
hex1d2331a52df

2002312123103 has 4 divisors (see below), whose sum is σ = 2002610848608. Its totient is φ = 2002013397600.

The previous prime is 2002312123099. The next prime is 2002312123121. The reversal of 2002312123103 is 3013212132002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2002312123103 - 22 = 2002312123099 is a prime.

It is a super-3 number, since 3×20023121231033 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002312183103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149352698 + ... + 149366103.

It is an arithmetic number, because the mean of its divisors is an integer number (500652712152).

Almost surely, 22002312123103 is an apocalyptic number.

2002312123103 is a deficient number, since it is larger than the sum of its proper divisors (298725505).

2002312123103 is an equidigital number, since it uses as much as digits as its factorization.

2002312123103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 298725504.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 2002312123103 its reverse (3013212132002), we get a palindrome (5015524255105).

The spelling of 2002312123103 in words is "two trillion, two billion, three hundred twelve million, one hundred twenty-three thousand, one hundred three".

Divisors: 1 6703 298718801 2002312123103