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20023122013 = 197115794541
BaseRepresentation
bin10010101001011110…
…001001100001011101
31220200110000222200121
4102221132021201131
5312001404401023
613110512554541
71306122505006
oct225136114135
956613028617
1020023122013
118545591a24
123a69852a51
131b714120bb
14d7d3c41ad
157c2cd6d5d
hex4a978985d

20023122013 has 16 divisors (see below), whose sum is σ = 21510195840. Its totient is φ = 18582782400.

The previous prime is 20023121999. The next prime is 20023122017. The reversal of 20023122013 is 31022132002.

It is a cyclic number.

It is not a de Polignac number, because 20023122013 - 229 = 19486251101 is a prime.

It is a super-3 number, since 3×200231220133 (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20023122017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 164523 + ... + 259063.

It is an arithmetic number, because the mean of its divisors is an integer number (1344387240).

Almost surely, 220023122013 is an apocalyptic number.

It is an amenable number.

20023122013 is a deficient number, since it is larger than the sum of its proper divisors (1487073827).

20023122013 is a wasteful number, since it uses less digits than its factorization.

20023122013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94788.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 20023122013 its reverse (31022132002), we get a palindrome (51045254015).

The spelling of 20023122013 in words is "twenty billion, twenty-three million, one hundred twenty-two thousand, thirteen".

Divisors: 1 19 71 157 1349 2983 11147 94541 211793 1796279 6712411 14842937 127535809 282015803 1053848527 20023122013