Base | Representation |
---|---|
bin | 11101001000110011000… |
… | …111010000110110111101 |
3 | 21002102022120211222000101 |
4 | 131020303013100312331 |
5 | 230301213422131023 |
6 | 4131503301401101 |
7 | 264443110514242 |
oct | 35106307206675 |
9 | 7072276758011 |
10 | 2002312302013 |
11 | 7021a3104591 |
12 | 28408a409191 |
13 | 116a81625b0a |
14 | 6ccaba015c9 |
15 | 37140ece1ad |
hex | 1d2331d0dbd |
2002312302013 has 8 divisors (see below), whose sum is σ = 2151738594432. Its totient is φ = 1856401922496.
The previous prime is 2002312301929. The next prime is 2002312302037. The reversal of 2002312302013 is 3102032132002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2002312302013 - 229 = 2001775431101 is a prime.
It is a super-3 number, since 3×20023123020133 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2002312302083) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 878977045 + ... + 878979322.
It is an arithmetic number, because the mean of its divisors is an integer number (268967324304).
Almost surely, 22002312302013 is an apocalyptic number.
It is an amenable number.
2002312302013 is a deficient number, since it is larger than the sum of its proper divisors (149426292419).
2002312302013 is a wasteful number, since it uses less digits than its factorization.
2002312302013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1757956451.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 2002312302013 its reverse (3102032132002), we get a palindrome (5104344434015).
The spelling of 2002312302013 in words is "two trillion, two billion, three hundred twelve million, three hundred two thousand, thirteen".
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