2002312313101 has 4 divisors (see below), whose sum is σ = 2002316867392. Its totient is φ = 2002307758812.

The previous prime is 2002312313041. The next prime is 2002312313119. The reversal of 2002312313101 is 1013132132002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002312313101 - 2¹¹ = 2002312311053 is a prime.

It is a super-3 number, since 3×2002312313101³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002312313161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1537605 + ... + 2523658.

It is an arithmetic number, because the mean of its divisors is an integer number (500579216848).

Almost surely, 2^{2002312313101} is an apocalyptic number.

It is an amenable number.

2002312313101 is a deficient number, since it is larger than the sum of its proper divisors (4554291).

2002312313101 is an equidigital number, since it uses as much as digits as its factorization.

2002312313101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4554290.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2002312313101 its reverse (1013132132002), we get a palindrome (3015444445103).

The spelling of 2002312313101 in words is "two trillion, two billion, three hundred twelve million, three hundred thirteen thousand, one hundred one".