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200233121111 = 422934734427
BaseRepresentation
bin1011101001111011010…
…0101111010101010111
3201010211120221110112122
42322132310233111113
511240034134333421
6231552534410155
720315651306252
oct2723664572527
9633746843478
10200233121111
1177a11416581
123298180095b
1315b60701c6a
149997046099
15531db722ab
hex2e9ed2f557

200233121111 has 4 divisors (see below), whose sum is σ = 200237897832. Its totient is φ = 200228344392.

The previous prime is 200233121063. The next prime is 200233121129. The reversal of 200233121111 is 111121332002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200233121111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200233121111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200233121611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2324921 + ... + 2409506.

It is an arithmetic number, because the mean of its divisors is an integer number (50059474458).

Almost surely, 2200233121111 is an apocalyptic number.

200233121111 is a deficient number, since it is larger than the sum of its proper divisors (4776721).

200233121111 is an equidigital number, since it uses as much as digits as its factorization.

200233121111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4776720.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 200233121111 its reverse (111121332002), we get a palindrome (311354453113).

The spelling of 200233121111 in words is "two hundred billion, two hundred thirty-three million, one hundred twenty-one thousand, one hundred eleven".

Divisors: 1 42293 4734427 200233121111