20023515121405 has 4 divisors (see below), whose sum is σ = 24028218145692. Its totient is φ = 16018812097120.

The previous prime is 20023515121403. The next prime is 20023515121447. The reversal of 20023515121405 is 50412151532002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15355378936836 + 4668136184569 = 3918594^2 + 2160587^2 .

It is not a de Polignac number, because 20023515121405 - 2¹ = 20023515121403 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20023515121403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2002351512136 + ... + 2002351512145.

It is an arithmetic number, because the mean of its divisors is an integer number (6007054536423).

Almost surely, 2^{20023515121405} is an apocalyptic number.

It is an amenable number.

20023515121405 is a deficient number, since it is larger than the sum of its proper divisors (4004703024287).

20023515121405 is an equidigital number, since it uses as much as digits as its factorization.

20023515121405 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4004703024286.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 20023515121405 its reverse (50412151532002), we get a palindrome (70435666653407).

The spelling of 20023515121405 in words is "twenty trillion, twenty-three billion, five hundred fifteen million, one hundred twenty-one thousand, four hundred five".