Search a number
-
+
20024012114 = 283120626579
BaseRepresentation
bin10010101001100001…
…100010110101010010
31220200111201012200022
4102221201202311102
5312002121341424
613110544023442
71306133203031
oct225141426522
956614635608
1020024012114
11854603a747
123a6a001b82
131b716642a2
14d7d576718
157c2e1095e
hex4a9862d52

20024012114 has 8 divisors (see below), whose sum is σ = 30397898160. Its totient is φ = 9891379396.

The previous prime is 20024012051. The next prime is 20024012119. The reversal of 20024012114 is 41121042002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×200240121142 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 20024012092 and 20024012101.

It is not an unprimeable number, because it can be changed into a prime (20024012119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60313124 + ... + 60313455.

It is an arithmetic number, because the mean of its divisors is an integer number (3799737270).

Almost surely, 220024012114 is an apocalyptic number.

20024012114 is a deficient number, since it is larger than the sum of its proper divisors (10373886046).

20024012114 is a wasteful number, since it uses less digits than its factorization.

20024012114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120626664.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 20024012114 its reverse (41121042002), we get a palindrome (61145054116).

The spelling of 20024012114 in words is "twenty billion, twenty-four million, twelve thousand, one hundred fourteen".

Divisors: 1 2 83 166 120626579 241253158 10012006057 20024012114