200240123113 has 4 divisors (see below), whose sum is σ = 200241307728. Its totient is φ = 200238938500.

The previous prime is 200240123089. The next prime is 200240123179. The reversal of 200240123113 is 311321042002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 200240123113 - 2¹⁷ = 200239992041 is a prime.

It is a super-2 number, since 2×200240123113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200240123183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 285931 + ... + 694432.

It is an arithmetic number, because the mean of its divisors is an integer number (50060326932).

Almost surely, 2^200240123113 is an apocalyptic number.

It is an amenable number.

200240123113 is a deficient number, since it is larger than the sum of its proper divisors (1184615).

200240123113 is an equidigital number, since it uses as much as digits as its factorization.

200240123113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1184614.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 200240123113 its reverse (311321042002), we get a palindrome (511561165115).

The spelling of 200240123113 in words is "two hundred billion, two hundred forty million, one hundred twenty-three thousand, one hundred thirteen".