Base | Representation |
---|---|
bin | 1001000110110001110110… |
… | …01111000101001111001111 |
3 | 2121220021210010211202111201 |
4 | 10203120323033011033033 |
5 | 10111033410110441221 |
6 | 110330543044330331 |
7 | 4134460433036314 |
oct | 443307317051717 |
9 | 77807703752451 |
10 | 20024131343311 |
11 | 642020612a477 |
12 | 22b49890a39a7 |
13 | b233628790c4 |
14 | 4d325d0c6d0b |
15 | 24ad1866d891 |
hex | 12363b3c53cf |
20024131343311 has 16 divisors (see below), whose sum is σ = 20380161620896. Its totient is φ = 19669003200000.
The previous prime is 20024131343309. The next prime is 20024131343393. The reversal of 20024131343311 is 11334313142002.
It is a cyclic number.
It is not a de Polignac number, because 20024131343311 - 21 = 20024131343309 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 20024131343311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20024131323311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 457139611 + ... + 457183411.
It is an arithmetic number, because the mean of its divisors is an integer number (1273760101306).
Almost surely, 220024131343311 is an apocalyptic number.
20024131343311 is a deficient number, since it is larger than the sum of its proper divisors (356030277585).
20024131343311 is an equidigital number, since it uses as much as digits as its factorization.
20024131343311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53914.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 20024131343311 its reverse (11334313142002), we get a palindrome (31358444485313).
The spelling of 20024131343311 in words is "twenty trillion, twenty-four billion, one hundred thirty-one million, three hundred forty-three thousand, three hundred eleven".
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