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2002430113 = 15311307923
BaseRepresentation
bin111011101011010…
…1010100010100001
312011112220222201021
41313112222202201
513100110230423
6530411005441
7100423242445
oct16726524241
95145828637
102002430113
11938357422
1247a739881
1325bb184b8
1414dd2c825
15babe295d
hex775aa8a1

2002430113 has 4 divisors (see below), whose sum is σ = 2003739568. Its totient is φ = 2001120660.

The previous prime is 2002430069. The next prime is 2002430123. The reversal of 2002430113 is 3110342002.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002430113 - 213 = 2002421921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002430123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 652431 + ... + 655492.

It is an arithmetic number, because the mean of its divisors is an integer number (500934892).

Almost surely, 22002430113 is an apocalyptic number.

It is an amenable number.

2002430113 is a deficient number, since it is larger than the sum of its proper divisors (1309455).

2002430113 is a wasteful number, since it uses less digits than its factorization.

2002430113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1309454.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 2002430113 is about 44748.5207911949. The cubic root of 2002430113 is about 1260.4311351102.

Adding to 2002430113 its reverse (3110342002), we get a palindrome (5112772115).

The spelling of 2002430113 in words is "two billion, two million, four hundred thirty thousand, one hundred thirteen".

Divisors: 1 1531 1307923 2002430113