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200243303141 = 728606186163
BaseRepresentation
bin1011101001111101101…
…1100101001011100101
3201010212022002202122212
42322133123211023211
511240044241200031
6231553540533205
720316133664420
oct2723733451345
9633768082585
10200243303141
1177a17140482
12329850b1205
1315b6285862b
1499985369b7
15531e9d412b
hex2e9f6e52e5

200243303141 has 4 divisors (see below), whose sum is σ = 228849489312. Its totient is φ = 171637116972.

The previous prime is 200243303119. The next prime is 200243303147. The reversal of 200243303141 is 141303342002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200243303141 - 230 = 199169561317 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200243303147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14303093075 + ... + 14303093088.

It is an arithmetic number, because the mean of its divisors is an integer number (57212372328).

Almost surely, 2200243303141 is an apocalyptic number.

It is an amenable number.

200243303141 is a deficient number, since it is larger than the sum of its proper divisors (28606186171).

200243303141 is an equidigital number, since it uses as much as digits as its factorization.

200243303141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28606186170.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 200243303141 its reverse (141303342002), we get a palindrome (341546645143).

The spelling of 200243303141 in words is "two hundred billion, two hundred forty-three million, three hundred three thousand, one hundred forty-one".

Divisors: 1 7 28606186163 200243303141