Base | Representation |
---|---|
bin | 1001000110110011011111… |
… | …10010110110010101101101 |
3 | 2121220101001121002101220002 |
4 | 10203121233302312111231 |
5 | 10111042211330302301 |
6 | 110331210344234045 |
7 | 4134521331116561 |
oct | 443315762662555 |
9 | 77811047071802 |
10 | 20025013134701 |
11 | 6420618955393 |
12 | 22b4b9446b925 |
13 | b23473468863 |
14 | 4d33042636a1 |
15 | 24ad6aca016b |
hex | 12366fcb656d |
20025013134701 has 8 divisors (see below), whose sum is σ = 20898452520000. Its totient is φ = 19151805969472.
The previous prime is 20025013134653. The next prime is 20025013134713. The reversal of 20025013134701 is 10743131052002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20025013134701 - 222 = 20025008940397 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20025013134781) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57878780 + ... + 58223733.
It is an arithmetic number, because the mean of its divisors is an integer number (2612306565000).
Almost surely, 220025013134701 is an apocalyptic number.
It is an amenable number.
20025013134701 is a deficient number, since it is larger than the sum of its proper divisors (873439385299).
20025013134701 is a wasteful number, since it uses less digits than its factorization.
20025013134701 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116110035.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 20025013134701 its reverse (10743131052002), we get a palindrome (30768144186703).
The spelling of 20025013134701 in words is "twenty trillion, twenty-five billion, thirteen million, one hundred thirty-four thousand, seven hundred one".
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