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200299470853 = 351157049123
BaseRepresentation
bin1011101010001011000…
…1110110000000000101
3201011000012210101021111
42322202301312000011
511240203131031403
6232003304445021
720320415260606
oct2724261660005
9634005711244
10200299470853
1177a45914079
123299ba79771
1315b71393171
1499a1b97dad
1553248cb56d
hex2ea2c76005

200299470853 has 4 divisors (see below), whose sum is σ = 200356523488. Its totient is φ = 200242418220.

The previous prime is 200299470817. The next prime is 200299470893. The reversal of 200299470853 is 358074992002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200299470853 - 225 = 200265916421 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200299470797 and 200299470806.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200299470893) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28521051 + ... + 28528072.

It is an arithmetic number, because the mean of its divisors is an integer number (50089130872).

Almost surely, 2200299470853 is an apocalyptic number.

It is an amenable number.

200299470853 is a deficient number, since it is larger than the sum of its proper divisors (57052635).

200299470853 is an equidigital number, since it uses as much as digits as its factorization.

200299470853 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57052634.

The product of its (nonzero) digits is 1088640, while the sum is 49.

The spelling of 200299470853 in words is "two hundred billion, two hundred ninety-nine million, four hundred seventy thousand, eight hundred fifty-three".

Divisors: 1 3511 57049123 200299470853