Base | Representation |
---|---|
bin | 11101001001011100000… |
… | …110101010100101111011 |
3 | 21002111002111220012120110 |
4 | 131021130012222211323 |
5 | 230304121000324011 |
6 | 4132055425355403 |
7 | 264466131115140 |
oct | 35113406524573 |
9 | 7074074805513 |
10 | 2003000011131 |
11 | 702516319629 |
12 | 284240798b63 |
13 | 116b60c509a2 |
14 | 6cd3509a3c7 |
15 | 37181574ba6 |
hex | 1d25c1aa97b |
2003000011131 has 32 divisors (see below), whose sum is σ = 3054453308928. Its totient is φ = 1143723260160.
The previous prime is 2003000011127. The next prime is 2003000011153. The reversal of 2003000011131 is 1311100003002.
It is not a de Polignac number, because 2003000011131 - 22 = 2003000011127 is a prime.
It is a super-2 number, since 2×20030000111312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2003000011121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 211037296 + ... + 211046786.
It is an arithmetic number, because the mean of its divisors is an integer number (95451665904).
Almost surely, 22003000011131 is an apocalyptic number.
2003000011131 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
2003000011131 is a deficient number, since it is larger than the sum of its proper divisors (1051453297797).
2003000011131 is a wasteful number, since it uses less digits than its factorization.
2003000011131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15891.
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 2003000011131 its reverse (1311100003002), we get a palindrome (3314100014133).
The spelling of 2003000011131 in words is "two trillion, three billion, eleven thousand, one hundred thirty-one".
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