Base | Representation |
---|---|
bin | 1011101010001011100… |
… | …0000110011110110111 |
3 | 201011000022212201102221 |
4 | 2322202320012132313 |
5 | 11240204041024343 |
6 | 232003403543211 |
7 | 20320435232203 |
oct | 2724270063667 |
9 | 634008781387 |
10 | 200301111223 |
11 | 77a46834554 |
12 | 329a052ab07 |
13 | 15b718189b5 |
14 | 99a20a3b03 |
15 | 5324b025ed |
hex | 2ea2e067b7 |
200301111223 has 4 divisors (see below), whose sum is σ = 200346117048. Its totient is φ = 200256105400.
The previous prime is 200301111221. The next prime is 200301111343. The reversal of 200301111223 is 322111103002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 200301111223 - 21 = 200301111221 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 200301111197 and 200301111206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200301111221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22496236 + ... + 22505137.
It is an arithmetic number, because the mean of its divisors is an integer number (50086529262).
Almost surely, 2200301111223 is an apocalyptic number.
200301111223 is a deficient number, since it is larger than the sum of its proper divisors (45005825).
200301111223 is an equidigital number, since it uses as much as digits as its factorization.
200301111223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45005824.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 200301111223 its reverse (322111103002), we get a palindrome (522412214225).
The spelling of 200301111223 in words is "two hundred billion, three hundred one million, one hundred eleven thousand, two hundred twenty-three".
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