Base | Representation |
---|---|
bin | 1001000110111100111111… |
… | …01101111110001111001111 |
3 | 2121220212012221202012110210 |
4 | 10203132133231332033033 |
5 | 10111133132201124444 |
6 | 110333412333333503 |
7 | 4135061564633226 |
oct | 443363755761717 |
9 | 77825187665423 |
10 | 20030112129999 |
11 | 64227a5127a94 |
12 | 22b5b78037293 |
13 | b23aa697883a |
14 | 4d3669533cbd |
15 | 24b06875d7b9 |
hex | 12379fb7e3cf |
20030112129999 has 4 divisors (see below), whose sum is σ = 26706816173336. Its totient is φ = 13353408086664.
The previous prime is 20030112129991. The next prime is 20030112130013. The reversal of 20030112129999 is 99992121103002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 20030112129999 - 23 = 20030112129991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20030112129991) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3338352021664 + ... + 3338352021669.
It is an arithmetic number, because the mean of its divisors is an integer number (6676704043334).
Almost surely, 220030112129999 is an apocalyptic number.
20030112129999 is a deficient number, since it is larger than the sum of its proper divisors (6676704043337).
20030112129999 is an equidigital number, since it uses as much as digits as its factorization.
20030112129999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6676704043336.
The product of its (nonzero) digits is 157464, while the sum is 48.
The spelling of 20030112129999 in words is "twenty trillion, thirty billion, one hundred twelve million, one hundred twenty-nine thousand, nine hundred ninety-nine".
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