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200302112011 = 1319151859069
BaseRepresentation
bin1011101010001011101…
…1111010110100001011
3201011000101202120021011
42322202323322310023
511240204320041021
6232003441224351
720320446601021
oct2724273726413
9634011676234
10200302112011
1177a47358451
12329a09320b7
1315b71aa9391
1499a2284711
155324c4dde1
hex2ea2efad0b

200302112011 has 4 divisors (see below), whose sum is σ = 200453972400. Its totient is φ = 200150251624.

The previous prime is 200302111967. The next prime is 200302112033. The reversal of 200302112011 is 110211203002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200302112011 - 213 = 200302103819 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200302111982 and 200302112000.

It is not an unprimeable number, because it can be changed into a prime (200302112051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75928216 + ... + 75930853.

It is an arithmetic number, because the mean of its divisors is an integer number (50113493100).

Almost surely, 2200302112011 is an apocalyptic number.

200302112011 is a deficient number, since it is larger than the sum of its proper divisors (151860389).

200302112011 is a wasteful number, since it uses less digits than its factorization.

200302112011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151860388.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 200302112011 its reverse (110211203002), we get a palindrome (310513315013).

Subtracting from 200302112011 its reverse (110211203002), we obtain a palindrome (90090909009).

The spelling of 200302112011 in words is "two hundred billion, three hundred two million, one hundred twelve thousand, eleven".

Divisors: 1 1319 151859069 200302112011