Base | Representation |
---|---|
bin | 101101100010110010110100… |
… | …111110111001011000101001 |
3 | 222021012210101121110200111012 |
4 | 231202302310332321120221 |
5 | 202223231303041444423 |
6 | 1550001553235113305 |
7 | 60122265214114211 |
oct | 5542626476713051 |
9 | 867183347420435 |
10 | 200303131203113 |
11 | 58906098743914 |
12 | 1a570109442835 |
13 | 879c672a1c2a3 |
14 | 3766a1a963241 |
15 | 18255265ac078 |
hex | b62cb4fb9629 |
200303131203113 has 8 divisors (see below), whose sum is σ = 200566628991168. Its totient is φ = 200039718274704.
The previous prime is 200303131203083. The next prime is 200303131203193. The reversal of 200303131203113 is 311302131303002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 200303131203113 - 234 = 200285951333929 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (200303131203193) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16490306 + ... + 25933307.
It is an arithmetic number, because the mean of its divisors is an integer number (25070828623896).
Almost surely, 2200303131203113 is an apocalyptic number.
It is an amenable number.
200303131203113 is a deficient number, since it is larger than the sum of its proper divisors (263497788055).
200303131203113 is an equidigital number, since it uses as much as digits as its factorization.
200303131203113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42429823.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 200303131203113 its reverse (311302131303002), we get a palindrome (511605262506115).
The spelling of 200303131203113 in words is "two hundred trillion, three hundred three billion, one hundred thirty-one million, two hundred three thousand, one hundred thirteen".
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