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2003042541 = 3667680847
BaseRepresentation
bin111011101100100…
…0000000011101101
312011121002002210210
41313121000003231
513100234330131
6530432053033
7100431403113
oct16731000355
95147062723
102003042541
11938735565
1247a994179
1325bca1196
1415004bab3
15bacb4146
hex776400ed

2003042541 has 4 divisors (see below), whose sum is σ = 2670723392. Its totient is φ = 1335361692.

The previous prime is 2003042539. The next prime is 2003042563. The reversal of 2003042541 is 1452403002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2003042541 - 21 = 2003042539 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003042501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333840421 + ... + 333840426.

It is an arithmetic number, because the mean of its divisors is an integer number (667680848).

Almost surely, 22003042541 is an apocalyptic number.

It is an amenable number.

2003042541 is a deficient number, since it is larger than the sum of its proper divisors (667680851).

2003042541 is an equidigital number, since it uses as much as digits as its factorization.

2003042541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 667680850.

The product of its (nonzero) digits is 960, while the sum is 21.

The square root of 2003042541 is about 44755.3632651998. The cubic root of 2003042541 is about 1260.5596197669.

Adding to 2003042541 its reverse (1452403002), we get a palindrome (3455445543).

The spelling of 2003042541 in words is "two billion, three million, forty-two thousand, five hundred forty-one".

Divisors: 1 3 667680847 2003042541