Base | Representation |
---|---|
bin | 11101001001100010000… |
… | …111111110111111011011 |
3 | 21002111100112221222212020 |
4 | 131021202013332333123 |
5 | 230304322330120443 |
6 | 4132113434345523 |
7 | 264501465512040 |
oct | 35114207767733 |
9 | 7074315858766 |
10 | 2003101020123 |
11 | 70256833a135 |
12 | 28426a58b2a3 |
13 | 116b78b58818 |
14 | 6cd446711c7 |
15 | 3718a378583 |
hex | 1d2621fefdb |
2003101020123 has 64 divisors (see below), whose sum is σ = 3197539418112. Its totient is φ = 1090576270080.
The previous prime is 2003101020121. The next prime is 2003101020143. The reversal of 2003101020123 is 3210201013002.
It is not a de Polignac number, because 2003101020123 - 21 = 2003101020121 is a prime.
It is a super-4 number, since 4×20031010201234 (a number of 50 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (2003101020121) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 263319586 + ... + 263327192.
It is an arithmetic number, because the mean of its divisors is an integer number (49961553408).
Almost surely, 22003101020123 is an apocalyptic number.
2003101020123 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
2003101020123 is a deficient number, since it is larger than the sum of its proper divisors (1194438397989).
2003101020123 is a wasteful number, since it uses less digits than its factorization.
2003101020123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9704.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 2003101020123 its reverse (3210201013002), we get a palindrome (5213302033125).
The spelling of 2003101020123 in words is "two trillion, three billion, one hundred one million, twenty thousand, one hundred twenty-three".
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