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2003102111 = 4549440339
BaseRepresentation
bin111011101100100…
…1110100110011111
312011121012010112002
41313121032212133
513100243231421
6530433232515
7100432041563
oct16731164637
95147163462
102003102111
1193877629a
1247aa0273b
1325bcc232a
141500656a3
15bacc6b0b
hex7764e99f

2003102111 has 4 divisors (see below), whose sum is σ = 2003547000. Its totient is φ = 2002657224.

The previous prime is 2003102093. The next prime is 2003102119. The reversal of 2003102111 is 1112013002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003102111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2003102092 and 2003102101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003102119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215621 + ... + 224718.

It is an arithmetic number, because the mean of its divisors is an integer number (500886750).

Almost surely, 22003102111 is an apocalyptic number.

2003102111 is a deficient number, since it is larger than the sum of its proper divisors (444889).

2003102111 is an equidigital number, since it uses as much as digits as its factorization.

2003102111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 444888.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 2003102111 is about 44756.0287670834. The cubic root of 2003102111 is about 1260.5721158890.

Adding to 2003102111 its reverse (1112013002), we get a palindrome (3115115113).

The spelling of 2003102111 in words is "two billion, three million, one hundred two thousand, one hundred eleven".

Divisors: 1 4549 440339 2003102111