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200310231132321 = 366770077044107
BaseRepresentation
bin101101100010111001011100…
…001010111110100010100001
3222021020110201102020110101020
4231202321130022332202201
5202223340323132213241
61550005125543200053
760122636155402242
oct5542713412764241
9867213642213336
10200310231132321
1158909101440802
121a57156b146029
1387a023494272b
1437670d1892cc9
1518257dea64b66
hexb62e5c2be8a1

200310231132321 has 4 divisors (see below), whose sum is σ = 267080308176432. Its totient is φ = 133540154088212.

The previous prime is 200310231132301. The next prime is 200310231132353. The reversal of 200310231132321 is 123231132013002.

200310231132321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200310231132321 - 25 = 200310231132289 is a prime.

It is a super-2 number, since 2×2003102311323212 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200310231132291 and 200310231132300.

It is not an unprimeable number, because it can be changed into a prime (200310231132301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33385038522051 + ... + 33385038522056.

It is an arithmetic number, because the mean of its divisors is an integer number (66770077044108).

Almost surely, 2200310231132321 is an apocalyptic number.

It is an amenable number.

200310231132321 is a deficient number, since it is larger than the sum of its proper divisors (66770077044111).

200310231132321 is an equidigital number, since it uses as much as digits as its factorization.

200310231132321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66770077044110.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 200310231132321 its reverse (123231132013002), we get a palindrome (323541363145323).

The spelling of 200310231132321 in words is "two hundred trillion, three hundred ten billion, two hundred thirty-one million, one hundred thirty-two thousand, three hundred twenty-one".

Divisors: 1 3 66770077044107 200310231132321