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200311013131 = 1590712592633
BaseRepresentation
bin1011101010001101110…
…1110111111100001011
3201011001000111210022021
42322203131313330023
511240214104410011
6232004400105311
720320615342555
oct2724335677413
9634030453267
10200311013131
1177a51387a49
12329a3905237
1315b738a4a08
1499a35204d5
15532590b471
hex2ea3777f0b

200311013131 has 4 divisors (see below), whose sum is σ = 200323621672. Its totient is φ = 200298404592.

The previous prime is 200311013099. The next prime is 200311013137. The reversal of 200311013131 is 131310113002.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131310113002 = 265655056501.

It is a cyclic number.

It is not a de Polignac number, because 200311013131 - 25 = 200311013099 is a prime.

It is a super-2 number, since 2×2003110131312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200311013137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6280410 + ... + 6312223.

It is an arithmetic number, because the mean of its divisors is an integer number (50080905418).

Almost surely, 2200311013131 is an apocalyptic number.

200311013131 is a deficient number, since it is larger than the sum of its proper divisors (12608541).

200311013131 is a wasteful number, since it uses less digits than its factorization.

200311013131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12608540.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 200311013131 its reverse (131310113002), we get a palindrome (331621126133).

The spelling of 200311013131 in words is "two hundred billion, three hundred eleven million, thirteen thousand, one hundred thirty-one".

Divisors: 1 15907 12592633 200311013131