2003111011111 has 4 divisors (see below), whose sum is σ = 2289269726992. Its totient is φ = 1716952295232.

The previous prime is 2003111011079. The next prime is 2003111011147. The reversal of 2003111011111 is 1111101113002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2003111011111 - 2⁵ = 2003111011079 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2003111011091 and 2003111011100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003111015111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143079357930 + ... + 143079357943.

It is an arithmetic number, because the mean of its divisors is an integer number (572317431748).

Almost surely, 2^{2003111011111} is an apocalyptic number.

2003111011111 is a deficient number, since it is larger than the sum of its proper divisors (286158715881).

2003111011111 is an equidigital number, since it uses as much as digits as its factorization.

2003111011111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 286158715880.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 2003111011111 its reverse (1111101113002), we get a palindrome (3114212124113).

The spelling of 2003111011111 in words is "two trillion, three billion, one hundred eleven million, eleven thousand, one hundred eleven".