2003112000121 has 4 divisors (see below), whose sum is σ = 2003114835072. Its totient is φ = 2003109165172.

The previous prime is 2003112000119. The next prime is 2003112000221. The reversal of 2003112000121 is 1210002113002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2003112000121 - 2¹ = 2003112000119 is a prime.

It is a super-3 number, since 3×2003112000121³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003112000221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591360 + ... + 2087086.

It is an arithmetic number, because the mean of its divisors is an integer number (500778708768).

Almost surely, 2^{2003112000121} is an apocalyptic number.

It is an amenable number.

2003112000121 is a deficient number, since it is larger than the sum of its proper divisors (2834951).

2003112000121 is a wasteful number, since it uses less digits than its factorization.

2003112000121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2834950.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 2003112000121 its reverse (1210002113002), we get a palindrome (3213114113123).

The spelling of 2003112000121 in words is "two trillion, three billion, one hundred twelve million, one hundred twenty-one", and thus it is an aban number.