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200311213002000 = 24353232626910067
BaseRepresentation
bin101101100010111010010110…
…101100100000110100010000
3222021020120020211210121100220
4231202322112230200310100
5202223344331012031000
61550005411220113040
760123002410222122
oct5542722654406420
9867216224717326
10200311213002000
1158909565700a51
121a5717a3b35780
1387a03601a24c9
143767186041212
15182584ad641a0
hexb62e96b20d10

200311213002000 has 480 divisors, whose sum is σ = 675277318235520. Its totient is φ = 51080649804800.

The previous prime is 200311213001989. The next prime is 200311213002001. The reversal of 200311213002000 is 200312113002.

It is a super-2 number, since 2×2003112130020002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is not an unprimeable number, because it can be changed into a prime (200311213002001) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 19897800967 + ... + 19897811033.

It is an arithmetic number, because the mean of its divisors is an integer number (1406827746324).

Almost surely, 2200311213002000 is an apocalyptic number.

200311213002000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 200311213002000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (337638659117760).

200311213002000 is an abundant number, since it is smaller than the sum of its proper divisors (474966105233520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

200311213002000 is a wasteful number, since it uses less digits than its factorization.

200311213002000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16408 (or 16369 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 200311213002000 its reverse (200312113002), we get a palindrome (200511525115002).

The spelling of 200311213002000 in words is "two hundred trillion, three hundred eleven billion, two hundred thirteen million, two thousand".