Base | Representation |
---|---|
bin | 101101100010111010011100… |
… | …101110010010110101111001 |
3 | 222021020120111220002120010020 |
4 | 231202322130232102311321 |
5 | 202223400032404213340 |
6 | 1550005425231441053 |
7 | 60123005045632563 |
oct | 5542723456226571 |
9 | 867216456076106 |
10 | 200311314132345 |
11 | 589096077a4749 |
12 | 1a571811986189 |
13 | 87a0378120650 |
14 | 3767195648333 |
15 | 1825854b8d9d0 |
hex | b62e9cb92d79 |
200311314132345 has 32 divisors (see below), whose sum is σ = 345158531582592. Its totient is φ = 98612878298112.
The previous prime is 200311314132337. The next prime is 200311314132421. The reversal of 200311314132345 is 543231413113002.
It is not a de Polignac number, because 200311314132345 - 23 = 200311314132337 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40929 + ... + 20015601.
It is an arithmetic number, because the mean of its divisors is an integer number (10786204111956).
Almost surely, 2200311314132345 is an apocalyptic number.
It is an amenable number.
200311314132345 is a deficient number, since it is larger than the sum of its proper divisors (144847217450247).
200311314132345 is a wasteful number, since it uses less digits than its factorization.
200311314132345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20026121.
The product of its (nonzero) digits is 25920, while the sum is 33.
Adding to 200311314132345 its reverse (543231413113002), we get a palindrome (743542727245347).
The spelling of 200311314132345 in words is "two hundred trillion, three hundred eleven billion, three hundred fourteen million, one hundred thirty-two thousand, three hundred forty-five".
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