Base | Representation |
---|---|
bin | 101101100010111010011100… |
… | …101111000101100010100011 |
3 | 222021020120111220111002222021 |
4 | 231202322130233011202203 |
5 | 202223400032432340003 |
6 | 1550005425240122311 |
7 | 60123005050456156 |
oct | 5542723457054243 |
9 | 867216456432867 |
10 | 200311314340003 |
11 | 58909607926769 |
12 | 1a571811a66397 |
13 | 87a0378194019 |
14 | 376719569dc9d |
15 | 1825854bd02bd |
hex | b62e9cbc58a3 |
200311314340003 has 16 divisors (see below), whose sum is σ = 210933992142720. Its totient is φ = 189696638814336.
The previous prime is 200311314339989. The next prime is 200311314340037. The reversal of 200311314340003 is 300043413113002.
It is a cyclic number.
It is not a de Polignac number, because 200311314340003 - 25 = 200311314339971 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 200311314340003.
It is not an unprimeable number, because it can be changed into a prime (200311314340903) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2614889500 + ... + 2614966102.
It is an arithmetic number, because the mean of its divisors is an integer number (13183374508920).
Almost surely, 2200311314340003 is an apocalyptic number.
200311314340003 is a deficient number, since it is larger than the sum of its proper divisors (10622677802717).
200311314340003 is a wasteful number, since it uses less digits than its factorization.
200311314340003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127026.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 200311314340003 its reverse (300043413113002), we get a palindrome (500354727453005).
The spelling of 200311314340003 in words is "two hundred trillion, three hundred eleven billion, three hundred fourteen million, three hundred forty thousand, three".
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