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200312102003 = 13107891428179
BaseRepresentation
bin1011101010001110001…
…0000001110001110011
3201011001002120002221212
42322203202001301303
511240214344231003
6232004435310335
720320630526246
oct2724342016163
9634032502855
10200312102003
1177a51a61042
12329a414b3ab
1315b73b96510
1499a372525d
155325a73dd8
hex2ea3881c73

200312102003 has 8 divisors (see below), whose sum is σ = 215740870800. Its totient is φ = 184886211168.

The previous prime is 200312101993. The next prime is 200312102033. The reversal of 200312102003 is 300201213002.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 200312102003 - 216 = 200312036467 is a prime.

It is a super-2 number, since 2×2003121020032 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (200312102033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 573833 + ... + 854346.

It is an arithmetic number, because the mean of its divisors is an integer number (26967608850).

Almost surely, 2200312102003 is an apocalyptic number.

200312102003 is a deficient number, since it is larger than the sum of its proper divisors (15428768797).

200312102003 is a wasteful number, since it uses less digits than its factorization.

200312102003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1438981.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 200312102003 its reverse (300201213002), we get a palindrome (500513315005).

The spelling of 200312102003 in words is "two hundred billion, three hundred twelve million, one hundred two thousand, three".

Divisors: 1 13 10789 140257 1428179 18566327 15408623231 200312102003