Base | Representation |
---|---|
bin | 101101100010111011001101… |
… | …100010011111010001100001 |
3 | 222021020122121222011111111212 |
4 | 231202323031202133101201 |
5 | 202223403222034333441 |
6 | 1550010042405315505 |
7 | 60123034252134140 |
oct | 5542731542372141 |
9 | 867218558144455 |
10 | 200312133121121 |
11 | 5890999802507a |
12 | 1a571a00105b95 |
13 | 87a04789c15a8 |
14 | 3767232317757 |
15 | 18258a1a16eeb |
hex | b62ecd89f461 |
200312133121121 has 8 divisors (see below), whose sum is σ = 232064154223104. Its totient is φ = 169344112540320.
The previous prime is 200312133121097. The next prime is 200312133121129. The reversal of 200312133121121 is 121121331213002.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 200312133121121 - 214 = 200312133104737 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200312133121129) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 196000129745 + ... + 196000130766.
It is an arithmetic number, because the mean of its divisors is an integer number (29008019277888).
Almost surely, 2200312133121121 is an apocalyptic number.
It is an amenable number.
200312133121121 is a deficient number, since it is larger than the sum of its proper divisors (31752021101983).
200312133121121 is an equidigital number, since it uses as much as digits as its factorization.
200312133121121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 392000260591.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 200312133121121 its reverse (121121331213002), we get a palindrome (321433464334123).
The spelling of 200312133121121 in words is "two hundred trillion, three hundred twelve billion, one hundred thirty-three million, one hundred twenty-one thousand, one hundred twenty-one".
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