Base | Representation |
---|---|
bin | 1001000110111111000011… |
… | …11011101001101100000111 |
3 | 2121220222002101001212020102 |
4 | 10203133201323221230013 |
5 | 10111142421042341403 |
6 | 110334114455354315 |
7 | 4135131244161452 |
oct | 443374173515407 |
9 | 77828071055212 |
10 | 20031223012103 |
11 | 64232151a5176 |
12 | 22b622808299b |
13 | b23c22b69724 |
14 | 4d3732ca6499 |
15 | 24b0d1043b88 |
hex | 1237e1ee9b07 |
20031223012103 has 8 divisors (see below), whose sum is σ = 20057647630176. Its totient is φ = 20004799716000.
The previous prime is 20031223012067. The next prime is 20031223012127. The reversal of 20031223012103 is 30121032213002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 20031223012103 - 236 = 19962503535367 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20031223012403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32088053 + ... + 32706353.
It is an arithmetic number, because the mean of its divisors is an integer number (2507205953772).
Almost surely, 220031223012103 is an apocalyptic number.
20031223012103 is a deficient number, since it is larger than the sum of its proper divisors (26424618073).
20031223012103 is an equidigital number, since it uses as much as digits as its factorization.
20031223012103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 660985.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 20031223012103 its reverse (30121032213002), we get a palindrome (50152255225105).
The spelling of 20031223012103 in words is "twenty trillion, thirty-one billion, two hundred twenty-three million, twelve thousand, one hundred three".
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