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2003130220103 = 7872545273469
BaseRepresentation
bin11101001001100011110…
…111010111111001000111
321002111102120220111200222
4131021203313113321013
5230304402314020403
64132120400254555
7264502301636135
oct35114367277107
97074376814628
102003130220103
11702582873551
1228427831145b
13116b81c1060c
146cd484b2755
153718cbe5338
hex1d263dd7e47

2003130220103 has 4 divisors (see below), whose sum is σ = 2005675494360. Its totient is φ = 2000584945848.

The previous prime is 2003130220087. The next prime is 2003130220139. The reversal of 2003130220103 is 3010220313002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2003130220103 - 24 = 2003130220087 is a prime.

It is a super-3 number, since 3×20031302201033 (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003130220183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1272635948 + ... + 1272637521.

It is an arithmetic number, because the mean of its divisors is an integer number (501418873590).

Almost surely, 22003130220103 is an apocalyptic number.

2003130220103 is a deficient number, since it is larger than the sum of its proper divisors (2545274257).

2003130220103 is an equidigital number, since it uses as much as digits as its factorization.

2003130220103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2545274256.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 2003130220103 its reverse (3010220313002), we get a palindrome (5013350533105).

The spelling of 2003130220103 in words is "two trillion, three billion, one hundred thirty million, two hundred twenty thousand, one hundred three".

Divisors: 1 787 2545273469 2003130220103